x^2+3.5x+2=0

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Solution for x^2+3.5x+2=0 equation: 



x^2+3.5x+2=0

a = 1; b = 3.5; c = +2;
Δ = b2-4ac
Δ = 3.52-4·1·2
Δ = 4.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.5)-\sqrt{4.25}}{2*1}=\frac{-3.5-\sqrt{4.25}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.5)+\sqrt{4.25}}{2*1}=\frac{-3.5+\sqrt{4.25}}{2}
$

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